36x^2+33x+6=0

Solution for 36x^2+33x+6=0 equation:

36x^2+33x+6=0

a = 36; b = 33; c = +6;
Δ = b2-4ac
Δ = 332-4·36·6
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*36}=\frac{-48}{72}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*36}=\frac{-18}{72}
=-1/4
$